( x y z ) ′ = ( − 10 10 0 b − 1 0 0 0 − 8 / 3 ) ( x y z ) . {\displaystyle {\begin{pmatrix}x\\y\\z\end{pmatrix}}'={\begin{pmatrix}-10&10&0\\b&-1&0\\0&0&-8/3\end{pmatrix}}{\begin{pmatrix}x\\y\\z\end{pmatrix}}.}
| − 10 − λ 10 0 b − 1 − λ 0 0 0 − 8 / 3 − λ | = − ( 8 / 3 + λ ) [ λ 2 + 11 λ − 10 ( b − 1 ) ] = 0. {\displaystyle {\begin{vmatrix}-10-\lambda &10&0\\b&-1-\lambda &0\\0&0&-8/3-\lambda \end{vmatrix}}=-(8/3+\lambda )[\lambda ^{2}+11\lambda -10(b-1)]=0.}